# SOLUTION: A single die with 6 faces numbered 1 through 6 is thrown thrice. What is the probability that the sum of the number appearing after each throw is more than 15? A)5/216 B)5/108 C

Algebra ->  Algebra  -> Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: A single die with 6 faces numbered 1 through 6 is thrown thrice. What is the probability that the sum of the number appearing after each throw is more than 15? A)5/216 B)5/108 C      Log On

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 Click here to see ALL problems on percentage Question 626440: A single die with 6 faces numbered 1 through 6 is thrown thrice. What is the probability that the sum of the number appearing after each throw is more than 15? A)5/216 B)5/108 C)5/36 D)1/5 E)1/6Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(57347)   (Show Source): You can put this solution on YOUR website!A single die with 6 faces numbered 1 through 6 is thrown thrice. What is the probability that the sum of the number appearing after each throw is more than 15? ---- Ways to win: 666-----1 way 665-----3 ways 664-----3 ways 655-----3 ways ----- Ans: 10/216 = 5/108 ======================= Cheers, Stan H. ======================= A)5/216 B)5/108 C)5/36 D)1/5 E)1/6 Answer by Edwin McCravy(8909)   (Show Source): You can put this solution on YOUR website!```The only combinations of rolls with sum exceeding 15 are these 4: 4+6+6 = 16 5+5+6 = 16 5+6+6 = 17 6+6+6 = 18 However, each of the first 3 rolls have 3!/2! = 3 distinguishable permutations. That's 3×3 or 9 ways. The fourth roll 6+6+6 can only be had in one way. So that's a total of 10 ways the sum can exceed 15. The number of possible rolls is 6·6·6 = 216 So the desired probability if 10 ways out of 216, or , which reduces to , choice B). Edwin```