SOLUTION: I'm having some difficulties solving mixture word problems, more in the area of creating a table. Any advice would be greatly appreciated. Here the problem! Suppose that a c

Question 467559: I'm having some difficulties solving mixture word problems, more in the area of creating a table. Any advice would be greatly appreciated.
Here the problem!
Suppose that a chemist is mixing two acid solutions, one of 20% concentration and the other 30% concentration. Which one of the following concentrations could not be obtained?
A. 22% B. 24% C. 28% D. 32%
I tried to setup a table as the one listed below
{Acid Amount} {Concentration Amount} {Total of A&C Amount}
20& of solution| x .2 .2(x)
30% of solution| x .3 .3(x)
Mixture |
I'm lost because it does not advise the total amount of concentration that is needed, therefore I do not know what to enter for mixutre. My equation will end up looking like this.
.2x + .3(X) = ?

Once again, thanks for taking the time to read this. I always try hard to solve a problem before submitting it here on Algebra.com
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Suppose that a chemist is mixing two acid solutions, one of 20% concentration and the other 30% concentration. Which one of the following concentrations could not be obtained?
A. 22% B. 24% C. 28% D. 32%
:
This is just a thought problem. If you think about it, you will come to the conclusion that when you mix two acid concentrations, the resulting percent has to be between the two solution's percent.
:
Note that A,B,C are between 20% and 30%, D which is 32%, on the other hand is not.
You cannot mix a solution that is less than 30 to get more than 30, can you?
:
Does this clear this up for you?
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