SOLUTION: in the equation How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol?
i wanna i dont under
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Question 429052: in the equation How many liters of an 11% alcohol solution should be mixed with 60 liters of a 5% alcohol solution to obtain a mixture that is 7% alcohol?
i wanna i dont under stand how you get 30 liters like what is the prosess that you must compute to get that
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
------ Percent ---------------- quantity
Alcohol A 5----------------60
Alcohol B 11----------------x
Total 7 ----------------60+x
5*60+11 *x=7(60+x)
300+11x=420+7x
11x-7x=420-300
4x=120
/4
x=30 gallons 11% Alcohol B
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