SOLUTION: How many liters of a 10% alcohol solution must be mixed with 40L of a 50% solution to get a 40% solution?
Algebra.Com
Question 309557: How many liters of a 10% alcohol solution must be mixed with 40L of a 50% solution to get a 40% solution?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
How many liters of a 10% alcohol solution must be mixed with 40L of a 50% solution to get a 40% solution?
let 10% alcohol required be x L
Concentration of 10% alcohol in the mix = 0.1x
.
40 L of 50% alcohol
concentration of this alcohol in the mix = 40*0.5= 20
.
Mixture concentration = 40% . quantity = (x+40)
= 0.4(x+40)
.
0.1x +20 =0.4(x+40)
0.1x +20 = 0.4x +16
-0.3x = -4
x= 13.33 liters
RELATED QUESTIONS
How many liters of a 10% alcohol solution must be mixed wih 40L of a 50% solution to get... (answered by jorel1380)
how many liters of a 10% alcohol solution must be mixed with how many liters of a 50%... (answered by mananth)
How many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to... (answered by Earlsdon)
HOW MANY LITERS OF A 10% ALCOHOL SOLUTION MUST BE MIXED WITH 40 L OF A 50% SOLUTION TO... (answered by HyperBrain)
how many liters of a 10% alcohol solution must be mixed with 40 L of a 50% solution to... (answered by mananth)
how many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% sotion to (answered by scott8148)
how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to... (answered by Alan3354)
How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solutionn (answered by jorel1380)
[ how many liters of a 40% alcohol solution must be mixed with 60 liters of a 70%... (answered by TimothyLamb)