SOLUTION: a restaurant offers the possibility of 168 three course dinners. Each dinner has an appetizer, an entree' and a dessert. If the number of appetizers decreases from 7 to 5, find h

Algebra.Com
Question 283522: a restaurant offers the possibility of 168 three course dinners. Each dinner has an appetizer, an entree' and a dessert. If the number of appetizers decreases from 7 to 5, find how many fewer possible three-course dinners the restaurant offers.
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
a*b*c=168
7*b*c=168
b*c=168/7=24
now we have
5*24=120
168-120=48 or 2*24
There are 48 fewer possible three course dinners

RELATED QUESTIONS

A restaurant has an early dining fixe prix(fixed price) dinner special that offers one... (answered by Boreal)
A restaurant menu has a price-fixed complete dinner that consists of an appetizer,... (answered by richwmiller)
The menu at a restaurant has 11 appetizers, 15 entrees, 10 desserts, and 8 beverages. The (answered by stanbon,checkley75)
The menu at a restaurant has 10 appetizers, 14 entrees, 11 desserts, and 10 beverages.... (answered by Edwin McCravy)
MAT 145: Topics In Contemporary Math Trees 3) The restaurant from #2 has a... (answered by ikleyn)
MAT 145: Topics In Contemporary Math Trees 3) The restaurant from #2 has a... (answered by math_tutor2020)
a restaurant offers 5 appetizers, 6 entrees, and 3 desserts. how many different ways can... (answered by Edwin McCravy)
Please help me with this question...I can't just figure it out. A local restaurant... (answered by Alan3354)
A menu has five choices for an appetizer, seven choices for the main dish, and three... (answered by Fombitz)