SOLUTION: In 2006, the # of Americans who were members of a health club was 42.7 million. This was an increase of 106% from th enumber of health club members in 1990. How many Americans were

Algebra.Com
Question 234412: In 2006, the # of Americans who were members of a health club was 42.7 million. This was an increase of 106% from th enumber of health club members in 1990. How many Americans were Health club members in 1990? Percentages are lost on me!
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
In 2006, the # of Americans who were members of a health club was 42.7 million.
This was an increase of 106% from th enumber of health club members in 1990.
How many Americans were Health club members in 1990?
:
The decimal equiv of 106% = 1.06
:
Let x = no. in 1990
;
original amt + the 106% increase = 42.7 million
x + 1.06x = 42.7
2.06x = 42.7
Divide both sides by 2.06
x =
x = 20.7 million in 1990
;
:

RELATED QUESTIONS

In 2006 the number of Americans who were members of a health club was 42.7 million. This (answered by drj)
In 2010, the number of American who were members of a health club was 45.3 million. This... (answered by sachi)
in 2006 the number of americans who were healthclub members was 42.7 million. this was... (answered by drj)
I am having to write an algebraic equation for each problem and solve it. I am not sure... (answered by mananth)
In 2005, the members of a club paid a total of $42 in subscription fees. In 2006, the... (answered by ankor@dixie-net.com)
In 2010, the population of a large city was 42.1 million. This represents an 11%... (answered by Boreal)
The 30 members of the tennis club meet every Tuesday. The 25 members of the golf club... (answered by greenestamps)
There are 55.8 million people in the united states without health insurance in 2005. This (answered by stanbon)
United States health expenses were $428.7 billion in 1985 and $991.4 billion in 1995.... (answered by josmiceli)