SOLUTION: A coffee shop owner tried to make his own special blend of coffee b adding a percentage of colombian cofee to his basic grind. After experimenting he decide that a 30 0/0 blend was

Question 23245: A coffee shop owner tried to make his own special blend of coffee b adding a percentage of colombian cofee to his basic grind. After experimenting he decide that a 30 0/0 blend was best. However, he was left with a supply of 20 0/0 and 50 0/0 columbian coffee blend. How many poubnds of the 20 0/0 blend would he have to add to the 50 0/0 blend to wind up with 100 lbs of the 30 0/0 blend?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Follow the columbian coffee in the blends.
Let the amount of 20% blend be "x"
Then the amount of 50% blend is "100-x"
EQUATION:
20%(x) + 50%(100-x) = 30%(100)
20x +5000-50x = 3000
-30x = -2000
x = 66 2/3 lbs. (amount of 20% blend)
100-x = 33 1/3 lbs. ( amount of 50% blend)
Cheers,
Stan H.
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