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put this solution on YOUR website!"Bill invested three times as much money at 9% as at 7.5%.
If he wanted his interest at the end of the year to be $1725,
what amount of money should he invest a 7.5%?"
;
Let x = amt invested at 7.5%
then "three times as much money at 9% as at 7.5%" therefore:
3x = amt invested at 9%
;
Write the interest equation:
.09(3x) + .075x = 1725
.27x + .075x = 1725
.345x = 1725
x =

x = $5000 invested at 7.5%
:
:
Check solution (15000 invested at 9%)
.09(15000) + .075(5000) =
1350 + 375 = 1725