# SOLUTION: Please help me solve this SAT practice question: There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then, interms of n, what percent of thos

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 Click here to see ALL problems on percentage Question 168490: Please help me solve this SAT practice question: There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then, interms of n, what percent of those enrolled are men? I started by saying Let n= # of men, which means that # of women= n+75 Then I wrote 100(n+75)= the percentage of women So in order to find the percentage of men in terms of n I wrote 100- 100(n+75) I just can't seem to get the solution that is a part of the choices given, which were: A.) [n/(n+75)]% B.) [n/(2n+75)]% C.) [n/((100(2n+75))]% D.) [100n/(n+75)]% E.) [100n/(2n+75)]%Answer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!There are 75 more women than men enrolled in Linden College. If there are n men enrolled, then, interms of n, what percent of those enrolled are men? I started by saying Let n= # of men, which means that # of women= n+75 -------- To get the percentage form n/[n+n+75] = n/[2n+75]% ================ Cheers, Stan H. A.) [n/(n+75)]% B.) [n/(2n+75)]% C.) [n/((100(2n+75))]% D.) [100n/(n+75)]% E.) [100n/(2n+75)]%