SOLUTION: In a survey concerning the smoking habits of consumer it was found that 55% smoke cigarette A, 50% smoke cigarette B,40% smoke cigarette C, 30% smoke cigarettes A and B, 20% smoke

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Question 1143506: In a survey concerning the smoking habits of consumer it was found that 55% smoke cigarette A, 50% smoke cigarette B,40% smoke cigarette C, 30% smoke cigarettes A and B, 20% smoke cigarettes A and C, 12% smoke cigarettes B and
C only 10% all three cigarettes. What percentage of the population did not smoke?

Answer by ikleyn(52798)   (Show Source): You can put this solution on YOUR website!
.

            Your formulation is not accurate.
            To be accurate (and to become a true Math problem),  it has to be re-written and re-edited.
            My editing is this:

            In a survey concerning the smoking habits of consumer it was found that 
            55% smoke cigarette A, 50% smoke cigarette B,40% smoke cigarette C, 
            30% smoke cigarettes A and B, 20% smoke cigarettes A and C, 12% smoke cigarettes B and C,
            while only 10% smoke all three types of cigarettes. What percentage of the population did not smoke? 


            The solution is below.


The percentage of those who smoke at least one of the three types of cigarettes is


    55 + 50 + 40 - 30 - 20 - 12 + 10 = 93  percents.      (*)


Therefore, 7% of the population do not smoke.      ANSWER


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The key to the solution is this alternate sum in the left side of (*).

For this formula, see the lessons
    - Advanced problems on counting elements in sub-sets of a given finite set
    - Challenging problems on counting elements in subsets of a given finite set
in this site.


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