SOLUTION: if you have 16 milliliters of a 24% glucose solution, how much of a 50% glucose solution must be added to this solution to get a final mixture with a glucose concentration of 35%?

Question 1043739: if you have 16 milliliters of a 24% glucose solution, how much of a 50% glucose solution must be added to this solution to get a final mixture with a glucose concentration of 35%?
Found 2 solutions by ankor@dixie-net.com, ikleyn:
Answer by ankor@dixie-net.com(22740)   (Show Source): You can put this solution on YOUR website!
if you have 16 milliliters of a 24% glucose solution, how much of a 50% glucose solution must be added to this solution to get a final mixture with a glucose concentration of 35%?
:
let x = amt of 50% solution required
:
.24(16) + .50x = .35(x+16)
3.84 + .5x = .35x + 5.6
.5x - .35x = 5.6 - 3.84
.15x = 1.76
x = 1.76/.15
x = 11.73 liter of 50% solution required
:

Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
On mixture problems, see the lessons
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Word problems on mixtures for antifreeze solutions
    - Word problems on mixtures for dry substances like coffee beans, nuts, cashew and peanuts
    - Word problems on mixtures for dry substances like candies, dried fruits
    - Word problems on mixtures for dry substances like soil and sand
    - Word problems on mixtures for alloys
    - Typical word problems on mixtures from the archive
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