Timothy has 1 gallon of 6% bleach, assume 94% is water.
Timothy decides to dilute the bleach separately. Timothy
pours 10mL, 9mL, 8mL, 7mL, 6mL, and 1mL, of the bleach
into 6 different containers and then fills the difference
to 10mL with water. Calculate the new percentage of the
bleach in each container.
Let n mL = 10mL, 9mL, 7mL, 6mL or 1mL
In each container, we are pouring in n mL of 6% bleach,
and 10-n mL of water
milliliters percent milliliters
of of bleach of pure
liquid as decimal bleach
Bleach solution n 0.06 0.06n
Water 10-n 0.00 0.00(10-n)
Mixture 10 0.06n
Then to find the percent of bleach in the mixture we divide
the number of milliliters of bleach solution by the number
of milliliters of liquid.
milliliters percent milliliters
of of bleach of pure
liquid as decimal bleach
Bleach solution n 0.06 0.06n
Water 10-n 0.00 0.00(10-n)
Mixture 10 0.06n/10 0.06n
percent of bleach as a decimal = 0.06n/10 = .006n
For n = 10 mL, 0.06(10)/10 = .06 = 6% <- (can't pour in any
water for it's full of 6%)
For n = 9 mL, 0.06(9)/10 = .054 = 5.4%
For n = 8 mL, 0.06(8)/10 = .048 = 4.8%
For n = 7 mL, 0.06(7)/10 = .042 = 4.2%
For n = 6 mL, 0.06(6)/10 = .036 = 3.6%
For n = 1 mL, 0.06(1)/10 = .006 = 0.6%
Edwin