# SOLUTION: please help! How much water should be added to 50ml of 25% acid solution to dilute it to a 10% acid solution? A 75 ml B. 7.5 ml C impossible to do Thank you!

Algebra ->  Algebra  -> Percentages: Solvers, Trainers, Word Problems and pie charts  -> Lessons -> SOLUTION: please help! How much water should be added to 50ml of 25% acid solution to dilute it to a 10% acid solution? A 75 ml B. 7.5 ml C impossible to do Thank you!      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Percentage and Pie Charts Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on percentage Question 48993: please help! How much water should be added to 50ml of 25% acid solution to dilute it to a 10% acid solution? A 75 ml B. 7.5 ml C impossible to do Thank you!Answer by tutorcecilia(2152)   (Show Source): You can put this solution on YOUR website!Use this basic formula: (% or rate of A)(Amount of A)+ (% or rate of B)(Amount of B) = C C can equal (% or rate of C)(A+B) or C can equal (% or rate of C)(Amount of C) . Change percentages to decimals: Example: 10% = .10 . Water is 0% acid. . (0%)(xml) + (25%)(50ml) = (10%)(xml + 50ml) (0)(x) + (.25)(50) = (.10)(x + 50) 0 + 12.50 = .10x + 5.0 12.50 = .10x + 5.0 [Solve for "x"] 7.5 = .10x 75ml = x So, add 75ml of water (0% acid) to 50ml of a 25% acid to yield 125ml of a 10% acid. . Check by plugging in all of the variables back into the original equation: (%A)(Amount A) + (%B)(Amount B) = (%C)(A+B) (0%)(75) + (.25)(50) = (.10)(125) 12.5 = 12.5 [Checks out]