# Questions on Algebra: Logarithm answered by real tutors!

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 Algebra: Logarithm Solvers Lessons Answers archive Quiz In Depth

 Question 385774: Rewrite the expression as a single logarithm: log(3,5) + 5log(3,2) Click here to see answer by stanbon(57967)

 Question 385928: if b is 1.2 and t is 4. first make x the subject and work out its value in this equation b = log4x - 2log t Click here to see answer by stanbon(57967)

 Question 386066: find the indicated composite for the pair functions, (f0g)(x): f(x)=3x+7, g(x)=4x-1 Click here to see answer by stanbon(57967)

 Question 386507: I am trying to figure out how to solve log5(x+1)-log5x=2 can you help Click here to see answer by ewatrrr(10682)

 Question 386648: What do you do when you have: 1/2Log(6)16X=3 [that is log, base 6) if you are solving for X, do you bring the "16X" to the other side? so it would be 1/2Log(6)6^3=16X I don't know; I feel like I'm messing this up.. Click here to see answer by stanbon(57967)

 Question 386461: How to solve for x: (exp x) - x = a Click here to see answer by Fombitz(13828)

 Question 386888: Please help! Solve lnx^2=ln(72-x) equivalent e^(lnx^2)=e^[ln(72-x)],because e^x is 1-1 function. equivalent x^2=72-x equivalent x^2+x-72=0 equivalent x1=[-1+sqr(1+4*1*72)]/2 , x2=[-1-sqr(1+4*1*72)]/2 equivalent x1=[-1+sqr(1+288)]/2, x2=[-1-sqr(1+288)]/2 equivalent x1=(-1+17)/2 , x2=(-1-17)/2 equivalent x1=16/2,x2=-18/2 equivalent x1=8,x2=-9 . Click here to see answer by robertb(4012)
 Question 386888: Please help! Solve lnx^2=ln(72-x) equivalent e^(lnx^2)=e^[ln(72-x)],because e^x is 1-1 function. equivalent x^2=72-x equivalent x^2+x-72=0 equivalent x1=[-1+sqr(1+4*1*72)]/2 , x2=[-1-sqr(1+4*1*72)]/2 equivalent x1=[-1+sqr(1+288)]/2, x2=[-1-sqr(1+288)]/2 equivalent x1=(-1+17)/2 , x2=(-1-17)/2 equivalent x1=16/2,x2=-18/2 equivalent x1=8,x2=-9 . Click here to see answer by dnanos(83)

 Question 386972: The number of bacteria is growing exponentially. If the number of bacteria rises from 100 to 350 in 6.5hours, how many bacteria will there be after 14 hours? Please help!! Click here to see answer by stanbon(57967)

 Question 387079: solve for x: log x + log(x-1) = log(4x) Click here to see answer by nerdybill(7008)

 Question 387121: The debt is 322.3 billion and over 30 years the debt increased to 10.2% each year. What was the year when it costed \$2,120? Click here to see answer by stanbon(57967)

 Question 387285: How much must be invested at 8% interest compounded continuously if 20 years from now the value of the account is to be \$100,000? Round your answer to the nearest highest dollar. Click here to see answer by stanbon(57967)

 Question 387299: Solve for x: log(x+1) + (log(x-1) = log8. Click here to see answer by nerdybill(7008)

 Question 387316: A population of bacteria grows according to A=5000e^(.025t) how long will it take for the population to double? Thank you Click here to see answer by richard1234(5390)

 Question 387340: For the function g:x |-> log(base 3)(x+2)-2 Find g^-1 (inverse). Explain how to verify your answer for g^-1. Thank you :) Click here to see answer by user_dude2008(1861)

 Question 387347: If f(x)=5-x-x^2, find in simplest form: 2f(x)-f(-x) Thank you :) Click here to see answer by stanbon(57967)

 Question 387320: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four places. b) write the formula for the amount of plutonium-238 present at the end of T days. c)How much of the initial amount will remain after 30 days? Round the answer to the nearest tenth gram. I know this seems like alot but I swear it's all one proublem just has Three parts to it, been having trouble, thank you sooo much in advance!!! :) Click here to see answer by stanbon(57967)

 Question 387363: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four places. b) write the formula for the amount of plutonium-238 present at the end of T days. c)How much of the initial amount will remain after 30 days? Round the answer to the nearest tenth gram. I know this seems like alot but I swear it's all one proublem just has Three parts to it, been having trouble, thank you sooo much in advance!!! :) Click here to see answer by stanbon(57967)

 Question 387364: If \$20,000 is invested at 4% compound semiannually, how much is present at the end of 15 years? Round your answer to the nearest lowest dollar. Thanks in advance :) Click here to see answer by stanbon(57967)

 Question 387362: use the properties of logarithms to elimate products, quotients and exponents from the following expression: log3[9 sqrt(x-5)/(x-1)^(5)] Thank you in advance, I'M really having a hard time understanding... Click here to see answer by stanbon(57967)
 Question 387362: use the properties of logarithms to elimate products, quotients and exponents from the following expression: log3[9 sqrt(x-5)/(x-1)^(5)] Thank you in advance, I'M really having a hard time understanding... Click here to see answer by Alan3354(31532)

 Question 387311: Use the exponential decay model A=Pe^(kt) to solve the following proublem. The half-life of plutonium-238 is days. The initial amount is 100 grams. a)find the value of K to four places. b) write the formula for the amount of plutonium-238 present at the end of T days. c)How much of the initial amount will remain after 30 days? Round the answer to the nearest tenth gram. I know this seems like alot but I swear it's all one proublem just has Three parts to it, been having trouble, thank you sooo much in advance!!! :) Click here to see answer by nerdybill(7008)

 Question 387373: why would logarithms give me extraneous solutions? Click here to see answer by Edwin McCravy(8999)

 Question 387442: what is x in this equation 2log(base 4)(2x)+log(base 4)(x-2) Click here to see answer by stanbon(57967)

 Question 387491: Use natural loarithms to solve the equation. Round to the nearest thoussandth. Problem: 6e^4x -2 = 3 Choices: (1) -o.448 (2) 0.327 (3) 0.067 (4) -0.046 How would you solve this? Thanks! Click here to see answer by Alan3354(31532)

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