Questions on Algebra: Logarithm answered by real tutors!

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Tutors Answer Your Questions about logarithm (FREE)


Question 37121: 3log (base 2) (5x)= 12
X=???

Click here to see answer by AnlytcPhil(958) About Me 
Question 37121: 3log (base 2) (5x)= 12
X=???

Click here to see answer by longjonsilver(2297) About Me 

Question 37107: Using a calculator, find log 1000 where log means log to the base of 10.
Answer:
b) Most calculators have 2 different logs on them: log, which is base 10, and ln, which is base e. In computer science, digital computers are based on the binary numbering system which means that there are only 2 numbers available to the computer, 0 and 1. When a computer scientist needs a logarithm, he needs a log to base 2 which is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:

Using this formula, find .
Answer:
Show work

Click here to see answer by longjonsilver(2297) About Me 

Question 37108: A computer is infected with the Boro virus. Assume that it infects 20 other computers within 5 minutes; and that these PCs and servers each infect 20 more machines within another five minutes, etc. How long until 100 million computers are infected
Click here to see answer by mbarugel(146) About Me 

Question 37101: HELP!!! I have to write the logarithmic equation in exponential form. For example, the exponential form of "log5 25 = 2" is "52 = 25".
The 3 after log goes small...as if it was an exponent but to the bottom.
log3 27 = 3

Click here to see answer by josmiceli(3003) About Me 

Question 37156: (simplify) In 8e^5
Click here to see answer by jcmtnez(53) About Me 

Question 37155: (log12) X + (log12)(X-1) = 1
Click here to see answer by fractalier(1804) About Me 

Question 37098: SOS! I really need help here. thank you very much.
convert to logarithmic equations. For example, the logarithmic form of "23 = 8" is "log2 8 = 3".

16 3/2 = 64

Click here to see answer by josmiceli(3003) About Me 

Question 37097: There is no way I can figure this one out:( Could you please help me out? TKS!!!
Evaluate each of the functions below at x = 1, 2, 4, 8, and 16. Plot the graph of each function. Classify each as linear, quadratic, polynomial, exponential, or logarithmic, and explain the reasons for your classifications. Compare how quickly each function increases, based on the evaluations and graphs, and rank the functions from fastest to slowest growing.
- f(x) = x3 - 3x2 - 2x + 1
- f(x) = ex
- f(x) = 3x - 2
- f(x) = log x
- f(x) = x2 - 5x + 6

Click here to see answer by josmiceli(3003) About Me 

Question 37287: use the properties of logarithms to condense the following expression:
1) 3 ln x + 2 ln (x+1)

Click here to see answer by jcmtnez(53) About Me 

Question 37289: use the properties of logarithms to expand the following expressions:
1) log(base10)7x^4
2) log(base7)x^1/2 / x
3) ln 3xy^2

Click here to see answer by jcmtnez(53) About Me 

Question 37290: find the domain of the given functions:
1) f(x)=ln(x-3)
2) f(x)=(1/4)ln x

Click here to see answer by fractalier(1804) About Me 

Question 37381: log(7-2x)=log(x+5)
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Question 37379: 9^x+4=27^x^2
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Question 37380: 9^x+4=27^x^2
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Question 37293: After t years the value V of a car that cost $14,000is V(t)=14000(3/4)^t. Find the value of the car 2 years after it was purchased. I came up with $7,875.00...is this correct?
Click here to see answer by fractalier(1804) About Me 

Question 37294: Solve for x:
1) 3^x=729 I got 6
2) 6^x-28=-8 I got 10/3
3) 4ln 3x =15 I got 14.17
am I correct?

Click here to see answer by fractalier(1804) About Me 

Question 37530: log4^8
Click here to see answer by josmiceli(3003) About Me 

Question 37532: log(base 3)(x+1)-log(base 3)(x)= log(base 3)4
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Question 37534: Condense the expression. 3log(base 10)2-log(base 10)y+1/3log(base 10)x
Click here to see answer by fractalier(1804) About Me 

Question 37533: solve for x. Log(base x)64=6
Click here to see answer by fractalier(1804) About Me 

Question 37537: Can i Have a answere for the following two questions, thanks very much

1) 0.04^log(base 0.2)3
2) 10^1+ln5

Click here to see answer by AnlytcPhil(958) About Me 

Question 37437: Solve for n.
2log n-log (n-1)= log4

Click here to see answer by fractalier(1804) About Me 

Question 37531: the natural base e is also referred to as the ________ number.
Click here to see answer by jcmtnez(53) About Me 

Question 37576: i have no idea to solve thiese type of question, if will be great if u can help me, thanks...
1. log(base 1.5)(3x-2)-log(base1.5)(56)less than log(base1.5)-log(1.5)(7)
2. log(base2)(x+3)+log(base2(x+2)greater than log(base2)(6)
3. xlog(base1/3)(7)-2log(base1/3)greater than zero

Click here to see answer by Nate(3495) About Me 

Question 37630: Is 10^3log(base 10)x = x^3 true?
Click here to see answer by Nate(3495) About Me 

Question 37759: I don't understand how to solve logarithms such as this:
3logx - log6 + log2.4 = 9

Click here to see answer by stanbon(26252) About Me 

Question 37816: log (2-3x) - log x = log 2x
Click here to see answer by longjonsilver(2297) About Me 

Question 38014: Evaluate the 3 is supposed to be over the check, where the invisible 2 usually goes. I got ln 1/e^1/3 whcich then equals -1/3, but I think I'm missing a step.
Click here to see answer by Earlsdon(4898) About Me 

Question 37582: A population increased to P0e4 in the first four years. What is the growth rate of this population? [Hint: P(t) = P0ekt]
Click here to see answer by fractalier(1804) About Me 

Question 38387: Use this formula logb a= loga/ logb, find log2 1000. I don't understand how you do this equation. I tried many different things and nothing works. Thanks, Christine
Click here to see answer by fractalier(1804) About Me 

Question 38399: If a bank compounds continuous, then the formula becomes simpler, that is A=Pe^rt where e is a constant and equals approximately 2.7183. Calculate A with continuous compounding. Use 20,000 at for 3 years at a rate of 8 percent.
This is what I have so far:
A= 20,000e^.08*2
A= 20,000e^.16
= ?
I am lost as to finding the answer, I don't understand what to do with e. Could you please help me? Thanks, Christine

Click here to see answer by fractalier(1804) About Me 
Question 38399: If a bank compounds continuous, then the formula becomes simpler, that is A=Pe^rt where e is a constant and equals approximately 2.7183. Calculate A with continuous compounding. Use 20,000 at for 3 years at a rate of 8 percent.
This is what I have so far:
A= 20,000e^.08*2
A= 20,000e^.16
= ?
I am lost as to finding the answer, I don't understand what to do with e. Could you please help me? Thanks, Christine

Click here to see answer by Nate(3495) About Me 

Question 38400: This question really has me stumped. Now suppose, instead of knowing t, we know tht the bank returned us $25,000 with the bank compounding continuously. Using logarithms, find how long we left the money in the bank (find t)
P= 25,000, R= .08, t=?
I could really use some help with this one. Thanks, Christine

Click here to see answer by Nate(3495) About Me 

Question 38414: Calculate the return A if the bank compounds daily (n=365)
20,000 & 8% (n=365)
This is what I have so far:
A= 20,000 ( 1+.08/365) 365*3
A= 20,000 (1.00)^1095
= ?
Thanks, Christine

Click here to see answer by fractalier(1804) About Me 

Question 38441: Most calculators have 2 different logs on them: log, which is base 10, and 1n, which is base e. In computer science, digital computers are based on the binary numbering system which means that there are only 2 numbers available to the computer, 0 and 1. When a computer scientist needs a logarithm, he needs a log to base 2 which is not on any calculator. To find the log of a number to any base, we can use a conversion formula as shown here:
log(subscript b)=loga (over) logb
Using this formula, find log (subscript 2) 1000.

Click here to see answer by fractalier(1804) About Me 

Question 38448: ASSUME THAT LOG 4=0.6021, LOG 5=0.699 AND LOG 6=0.7782 USE THE PRPETIES OF LOGARITHMS TO EVALUATE EACH EXPRESSION ROUNF YOUR ANSWER TO THE NEAREST THOUSANDTH
1.) log 0.8
2.) log 30

Click here to see answer by fractalier(1804) About Me 

Question 38457: ASSUME THAT LOG 4=0.6021, LOG 5=0.699 AND LOG 6=0.7782 USE THE PRPETIES OF LOGARITHMS TO EVALUATE EACH EXPRESSION ROUNF YOUR ANSWER TO THE NEAREST THOUSANDTH

1.)log125
2.) log1.5
3.) log1/4
4.) log 1/25
EXPAND THE LOGARITHM
1.) log3m^4n-^2


Click here to see answer by longjonsilver(2297) About Me 

Question 38624: Simplify the expression log9 - (log12 - log4)
Please show your working out, and thanks in advance for your help

Click here to see answer by Earlsdon(4898) About Me 

Question 38623: Express 4^3 = 64 in logaritnmic form
Please show your working out, and thank you in advance for your help

Click here to see answer by Earlsdon(4898) About Me 

Question 38648: I need to evalute the expression:
y^4/9(y^-4/9 + 4y ^5/9)
any help with this,i cant make sense of it or solve it. I need to multiply and assume all numbers are positive.
Thanks for your help

Click here to see answer by hellyeah(21) About Me 

Question 38652: Hello all,
I need help to write the equation in logarithmic form !!
(1/5)^-6 = 15625

I need to find the value of x with this problem!!
log 4 1024 = x

Please help, i am lost here

Click here to see answer by Nate(3495) About Me 

Question 38684: Expand using properties of logarithms:
log (xy^2)
------
(Y)

Click here to see answer by jcmtnez(53) About Me 

Question 38907: Hello,
I need help with a few problems i cant seem to work out for homework.
1:Solve for x: 9^x=3
2:Solve for x: 2^9x^-4=32
3:Solve for x: log10^7=log10x-log10^2

Thanks

Click here to see answer by AnlytcPhil(958) About Me 

Question 39095: Hi, please help me on this question, I've been thinking about it for a long time.
If and , determine
a) the values of x and y in terms of a, using positive indices.
b) an equation of x in terms of y
I've tried using the first log rule to do both equations and came up with and resectively but I don't know where to go from there. I also transformed it into an exponential equation and respectively and still have no clue of what to do.
Thank you.

Click here to see answer by fractalier(1804) About Me 

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