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Tutors Answer Your Questions about logarithm (FREE)
Question 208147: the number of homes built can be modeled by an exponential function,
H= p * at , where p is the number of new homes built in the first year recorded.
p=10 t =3 a=2
I'm not sure how to calculate
Click here to see answer by rfer(2688)   |
Question 208183: the number of homes built can be modeled by an exponential function,
H= p * at , where p is the number of new homes built in the first year recorded.
p=10 t =3 a=2
I'm not sure how to calculate : the number of homes built can be modeled by an exponential function,
H= p * a^t , where p is the number of new homes built in the first year recorded.
p=10 t =3 a=2
I'm not sure how to calculate
Click here to see answer by rapaljer(3610) |
Question 209155: can someone please help.
solve each equation for x
1. 4^(x + 1) = 4^(3x - 5)
2.8^2x = 8^(3x - 1)
3.10^6x = 100^(x + 6)
use your calculator to solve for x.round to the nearest thousandth
1.10^2.3 = x
2.e^x = 9
3.10^x = 15
4.e^ -1.5 = x
thanks for the help.I really appreciate it.
Click here to see answer by stanbon(26259) |
Question 209694: I had 10 problems on this.
i was able to complete all except 2.
e^2x - 3e^x + 2 = 0
i believe i am supposed to move the 2 to the other side.
but im not quite sure how to solve this problem
id greatly appreciate ur help
Click here to see answer by nerdybill(2446)  |
Question 209715: i have the problem:
ln(x+1)^2=2
i worked it out as:
ln(x+1)^2=2
(x+1)^2=e^2
2(x+1)=7.38906
2x+2=7.38906
2x\2 = 5.38906
x=2.69453
i know i did something wrong becausemy answer is not working out.
help me plz!
Click here to see answer by Alan3354(6059)  |
Question 209720: i have the problem:
ln(x+1)^2=2
i worked it out as:
ln(x+1)^2=2
(x+1)^2=e^2
2(x+1)=7.38906
2x+2=7.38906
2x\2 = 5.38906
x=2.69453
i know i did something wrong becausemy answer is not working out.
help me plz!
what did i do wrong?
thanks in advanced
Click here to see answer by stanbon(26259) |
Question 209750: i worked this problem like this:
(e^2x) - (3e^x) + 2 = 0
(e^2x) - (3e^x) = -2
e^(2x\x^3) = e^(-2)
(2\x^2)= e^(-2)
2= e^(-2x^2)
(2\e^-2) = x^2
sqrt(14.778)= sqrt(x^2)
x=3.844
i tried my answer. but it doesnt work out.
Click here to see answer by stanbon(26259) |
Question 209731: i worked this problem like this:
e^2x - 3e^x + 2 = 0
e^2x - 3e^x = -2
e^(2x\x^3) = e^(-2)
(2\x^2)= e^(-2)
2= e^(-2x^2)
(2\e^-2) = x^2
sqrt(14.778)= sqrt(x^2)
x=3.844
i tried my answer. but it doesnt work out.
what did i do wrong?
thanks in advance
Click here to see answer by jsmallt9(590) |
Question 211020: Find the pH of an acidic substance of your choice. Using this pH, show how to find the hydrogen ion concentration, [H+], of the substance using the formula. Discuss the meaning of pH and [H+], the pH scale and why your chosen substance is acidic. Use scientific notation or enough decimal places so that your answer has at least 3 place values. For example, either use 3.44*10-6 or 0.00000344.
I picked Baking soda. Baking soda is NaHCO3.
The formula is:
pH = -log10 [H+]
Baking soda has a pH of 9. It is a base, since the pH is above 7.
You first plug 9 into the formula:
9 = -log10 [H+]
Then divide by -1:
-9 = log10 [H+]
Take 10 on each side:
10^-9 = 10log10 [H+]
Simplify:
10^-9 = [H+]
[H+] = 10^-9 mol/L
Click here to see answer by stanbon(26259) |
Question 211035: Using the Library, web resources, and/or other materials, find a real-life application of a quadratic function. State the application, give the equation of the quadratic function, and state what the x and y in the application represent. Choose at least two values of x to input into your function and find the corresponding y for each. State, in words, what each x and y means in terms of your real-life application. Please see the following example. Do not use any version of this example in your own post. You may use other variables besides x and y, such as t and S depicted in the following example, but you may not use that example. Be sure to reference all sources using APA style.
Typing hint: To type x-squared, use x^2. Do not use special graphs or symbols because they will not appear when pasted to the Discussion Board.
When thrown into the air from the top of a 50 ft building, a ball’s height, S, at time t can be found by S(t) = -16t^2 + 32t + 50. When t = 1, s = -16(1)^2 + 32(1) + 50 = 66. This implies that after 1 second, the height of the ball is 66 feet. When t = 2, s = -16(2)^2 + 32(2) + 50 = 50. This implies that after 2 seconds, the height of the ball is 50 feet.
I used this. I wanted to know if I was correct.
Real life quadratic function application:
The formula s=-16t^2+vOt+sO
sO=initial height
vO=velocity in feet per second
t=time
The initial height of the mountain where you are standing is 300 feet.
I launch a rock in the air at 52 feet per second.
I want to find out how high it will be after 3 seconds.
Now let’s do the formula.
s=-16t^2+vOt+sO
=-16(3) ^2+52(3) +300
=-16(9) +156+300
=-144+465
s=312
So at 3 seconds, it's 312
This accurately describes the rock's height at any given time from the time of launch to the time.
Click here to see answer by stanbon(26259) |
Question 211372: Could someone please tell me if I did this right.
Evaluate the logarithmic equation for three values of x that are greater than 1, three values between 0 and 1, x to =0.
y=log3.5^x
x=2 so y=0.55
x=3 so y=0.88
x=4 so y=1.11
x=0.2 so y= - 1.28
x=0.5 so y= - 0.55
x=0.7 so y= - 0.28
x=1 so y=0
Click here to see answer by RAY100(1637) |
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