Tutors Answer Your Questions about logarithm (FREE)
Question 149929: Exponential and Logarithmic Functions
Like always reading and translating these are tough. Thank you for helping
Problem: The level of a prescription drug in the human body over time can be found using the formula:
where D is the amount taken every n hours and H is the drug’s half-life in hours.
1.If 2.5 milligrams of Lorazepam with a half-life of 14 hours is taken every 24 hours, then to what level does the drug build up over time?
2.If a doctor wants the level of Lorazepam to build up to a level of 5.58 milligrams in a patient taking 2.5 milligram doses, then how often should the doses be taken?
3.What is the difference between taking 2.5 milligrams of Lorazepam every 12 hours and taking 5 milligrams every 24 hours?
4. What mathematical concepts are applyied and explain the steps in order to solve this problem
Thank you
Click here to see answer by stanbon(57361) |
Question 149931: I have a question in regards to a problem that was already submitted and solved. THe question number is 149823, and it was solved by, vleith(790). THe question i have is around the second problem. I am having trouble understanding how we got the equation or answer of (1-(0.5)^n/14)= 2.5/5.58, and the next step says -(0.5)^n/14 = -0.552. How did we get - 0.552? and i am hoping this will help me understand the rest of the this problem. but if there is anyway of explaining the following steps to solve for this would be helpful.
Click here to see answer by jim_thompson5910(28595) |
Question 149866: How do I complete this problem? For the exponential function ex and logarithmic function log x, graphically show the effect if x is doubled.
How do I calculate and plot these?
1. ex and e2x
2 logx and log2x
Correct reasoning of the effect of doubling the value of x in logarithmic and exponential functions
This is one tough question. Thanks so much.
Click here to see answer by josmiceli(9684)  |
Question 149979: Please help, I don't even know where to start with this problem!
Which of the following describes the steps involved in using the graph of y=3 cos x + 3
1. Stretch the graph vertically by a factor of 3 and shift it to the left 3 units.
2. Stretch the graph vertically by a factor of 3 and shift it down 3 units.
3. Stretch the graph vertically by a factor of 3 and shift it to the right 3 units.
4. Stretch the graph vertically by a factor of 3 and shift it up 3 units.
Thank you again, this means so much, Natalie
Click here to see answer by oscargut(891)  |
Question 150439: Ok, here is a real life equation that I need to solve for a calulation I'm doing at work. I need to solve for x in the following equation:
A = B * (1+i)^x + C * (1+j)^x
where i and j are interest rates and A, B and C are dollar amounts. In story problem language the problem is: How long will it take for Fund B and Fund C combined take to grow to amount A given that Fund B is growing at i% and Fund C is growing at j%? I know I can't just multiply both sides by ln in this equation and have it work, so I'm not sure what to do with it.
Click here to see answer by stanbon(57361) |
Question 150694: Hello E-Instructors :)
Would someone kindly show me how to solve this problem correctly?
Problem: The level of a prescription drug in the human body over time can be found using the formula:
L= ___D___
''''''''1-(1/2)^n/H
where D is the amount taken every 'n' hours and H is the drug's half-life in hours.
(''''These marks are merely spacers and not intended to be part of the equation).
1. If 2.5 milligrams of Lorazepam with a half-life of 14 hours is taken
every 24 hours, then to what level does the drug build up over time?
So far I think that the formula may look like this:
2.5 = ___24________
'''''''''''''1-(1/2)^24/14
Then maybe this:
2.5 = ___24____
'''''''''''''0.3047534
2.5 = 69.057991
Then, I don't know what to do next or if what I've done is even close to being right. :P
2. If a doctor wants the level of Lorazepam to build up to a level
of 5.58 milligrams in a patient taking 2.5 milligram doses, then how
often should the doses be taken?
I'm completely in the dark about this one.
3. What is the difference between taking 2.5 milligram of Lorazepam
every 12 hours and taking 5 milligrams every 24 hours?
This one, I might subtract results from these two equations:
2.5 = ___12_________
''''''''''''1-(1/2)^12/14
from
5 = ___24_______
''''''''''1-(1/2)^24/14
Well, that would be after I have learned how to solve the first question
correctly. ;)
Thank you so much for sharing your valuable knowledge with a mathematically challenged damsel like myself.
Grateful,
J. ;)
Click here to see answer by edjones(7569)  |
Question 151178: Story problem: A can of soda at 79 degrees F is placed in a refrigerator that maintains a constant temperature of 36 degrees F. The temperature T of the soda t minutes after it is placed in the refrigerator is given by T(t)=36+43e^-.058t.
Part a) Find the temperature to the nearest degree of the soda 10 minutes after it is placed in the refrigerator.
I substituted 10 into the equation and got 60 degrees F. I understand this part.
Part b) When, to the nearest minute, will the temperature of the soda be 45 degrees F? HELP! I think that you need to plug in equations to graph it but I don't know what to plug in.
Thanks,
Rose
Click here to see answer by vleith(2825) |
Question 151243: In the formula A=I^ekt, A is the amount of radioactive material remaining from an initial amount I at a given time t and k is a negative constant determined by the nature of the material. An artificat is discovered at a certain site. If it has 53% of the carbon of the carbon-14 it originally contained, what is the approximate age of the artificat? (carbon-14 decays at the rate of 0.0125% annually.) Round to the nearest year.
Click here to see answer by stanbon(57361) |
Question 151244: Suppose the amount of a radioactive element remaining in a sample of 100 milligrams after x years can be described by A(x)=100e^-0.01657x. How much is remaining after 257 years. Round the answer to the nearest hundredth of a milligram.
Click here to see answer by stanbon(57361) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890
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