SOLUTION: How do you do this exercise: logB = 3(log x -1) -2 (1

SOLUTION: How do you do this exercise: logB = 3(log x -1) -2 (1 - log y)

Question 991094: How do you do this exercise:
logB = 3(log x -1) -2 (1 - log y)
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Is this it:

If so,

Hope I got it
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
logB = 3(log x -1) -2 (1 - log y)
----
I'll assume you want to solve for "y":
---
2(1-log(y)) = 3(log(x)-1) - log(B)
-----------
2 - 2log(y) = 3log(x) - 3 - log(B)
----------
-2log(y) = log(x^3/B) - 5
------------
log(y) = (5/2)-log[sqrt(x^3/B)]
-------
log(y) = (5/2) - log[x^(3/2)/B^(1/2)]
---
y = 10^[(5/2) - log[x^(3/2)/B^(1/2)]]
----------
Cheers,
Stan H.
RELATED QUESTIONS
How do you write this as a single logarithm: 1/3(log x + log z) - 2 log... (answered by dnanos,Edwin McCravy)
How do i condense: 3 log x + 1/2 log y - log 8 - 2 log 3z Thank... (answered by lwsshak3,MathLover1)
how do you solve... (answered by Theo)
How do I work log(x-1)-log(x+6)=log(x-2)-log(x+3) (answered by josgarithmetic)
How do i write these as a single logarithm? 1) (log 3 - log 4) - log 2 2) log 2 +... (answered by Boreal)
How do you solve this equation? Log base 3 x+ Log base 3... (answered by ankor@dixie-net.com)
How do you solve:... (answered by jsmallt9)
How do you solve this logarithmic equation:... (answered by jim_thompson5910,vleith)
How do you square a log? Specifically {{{ (log( 3, x ))^2 }}}. The entire problem is {{{... (answered by Alan3354)