SOLUTION: log2 (x+y)=3 and x2-3y2=4, solve the above equation
Algebra.Com
Question 986306: log2 (x+y)=3 and x2-3y2=4, solve the above equation
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log2 (x+y)=3
x2-3y2=4
-------------
--> x+y = 8
y = 8-x
Sub for y in the 2nd equation.
==============
Use ^ (Shift 6) for exponents.
x^2 - 3y^2 = 4
RELATED QUESTIONS
solve the simultaneous equation:
1.) log2^x - log2^y =2, log2^(x-2y) =3 (answered by Alex.33,MathTherapy)
Solve the equation.
2 log2(x) − log2(x - 3) = 2 +... (answered by Earlsdon)
log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round. (answered by lwsshak3)
Solve y=log2(5x-4)
y=3+log2(x-1)
(answered by stanbon)
Solve the following simultaneous equation
1) log8(xy) = 3
2) log2(x) * log2(y) =... (answered by Fombitz)
Solve the logarithmic equation for x.
log2 3 + log2 x = log2 5 + log2(x − 2)
x = (answered by lwsshak3)
1) solve the equation 4^x-3*2^x-4=0
2)solve the equation... (answered by Fombitz,jsmallt9)
solve for x
log2 (y+4) + log2 y =5
(answered by solver91311)
solve logarithmic equation... (answered by rfadrogane)