SOLUTION: Please help. Find the real solution to:
{{{log(2)t+log(2)(t+1)=1}}}
Answer: t=1
But how? I have tried:
{{{2^(1)+2^(t+1)=t^2+t}}}
{{{2^(x+1)=e^(2)+t}}}
and
{{{log(2)t+l
Algebra.Com
Question 981943: Please help. Find the real solution to:
Answer: t=1
But how? I have tried:
and
Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
Your equation shown is ambiguous. One would only try guessing the base is meant to be 2.
, with the base of 2.
2 to no power gives any negative value, so you can only accept t=1.
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