SOLUTION: Solve equation:
Log base 2 of X plus log base 2 of (3x+1) equals 1
Not sure how my book got the answer:2/3
Algebra.Com
Question 980596: Solve equation:
Log base 2 of X plus log base 2 of (3x+1) equals 1
Not sure how my book got the answer:2/3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ +\ \log_2(3x\ +\ 1)\ =\ 1)
The sum of the logs is the log of the product, so:
\ =\ 1)
Use the definition of the log function:
 \ \ \Rightarrow\ \ b^y = x)
So
\ =\ 1\ \ \Rightarrow\ \ 3x^2\ +\ x\ =\ 2)
Just solve the quadratic. Discard any root not in the domain of ANY of the log functions in the original problem or intermediate step in the solution.
John
My calculator said it, I believe it, that settles it
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