SOLUTION: Prove that 2log(16/15)+log(25/24)-log(32/27)=0

Question 980074: Prove that 2log(16/15)+log(25/24)-log(32/27)=0
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2log(16/15)+log(25/24)-log(32/27)=0;
log {16^2*25*27)/(15^2*24*32}
256*25*27/225*24*32 = 256*675/225*768
256 is 1/3 of 768
675 is 3 times 225
3*1/3=1
log 1=0
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