SOLUTION: The amount of money in an investment is modeled by the function A(t)=600(1.054)^t. The variable A represents the investment balance in dollars, and t the number of years. What

Algebra.Com
Question 978545: The amount of money in an investment is modeled by the function A(t)=600(1.054)^t. The variable A represents the investment balance in dollars, and t the number of years.
What is the doubling time for the investment? Round answer to 1 decimal place.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
The amount of money in an investment is modeled by the function A(t)=600(1.054)^t. The variable A represents the investment balance in dollars, and t the number of years.
What is the doubling time for the investment? Round answer to 1 decimal place.
----
The investment has doubled when A(t) = 1200
---
Solve::
2 = (1.054)^t
---
t = log(2)/log(1.054)
---
t = 13.2 years
-------------
Cheers,
Stan H.

RELATED QUESTIONS

An initial investment of $21,500 is placed in a bank account that earns 3.92% interest,... (answered by josgarithmetic)
The average monthly temperature of a town can be modeled by the function... (answered by greenestamps)
I kinda have an idea, but I'm confused. =_= Q1: The number of bacteria in a certain... (answered by jorel1380)
The performance of a certain stock can be modeled by the equation d(t)=2000(1.2)^t. If... (answered by fcabanski)
The height (in feet) of the water level in a reservoir over a 1 year period is modeled by (answered by nerdybill)
Jonah deposits $2500 into account with an annual rate of 5%, compounded annually. The... (answered by ewatrrr)
The amount A of money on deposit for t years in an account earning simple interest is a (answered by stanbon)
Where do i start to set this up? Suppose that 79,000 is invested at 5 and 1/2%... (answered by stanbon)
Y(t) is below 10e^(0.05t), 0<=t<=10 (600)/(20+10e^(-0.5(t-12))), t>12 f(t) is... (answered by ikleyn)