SOLUTION: Solve for x in terms of k.
log_(5) x - log_(5) (x+10) = log_(5) k.
x =
Find x if k = 1/2
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Question 977515: Solve for x in terms of k.
log_(5) x - log_(5) (x+10) = log_(5) k.
x =
Find x if k = 1/2
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The difference of the logs is the log of the quotient, so:
\ -\log_5(x\ -\ 10)\ =\ \log_5(k) \Right\ \log_5\left(\frac{x}{x\,-\,10}\right)\ =\ \log_5(k))
Now, if you consider the fact that:
\ =\ \log_b(\beta))
if and only if 
You should be able to finish this yourself.
John
My calculator said it, I believe it, that settles it
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