SOLUTION: The integral of log3 (x^2) - log3 (x+6)= 1. After solving this I find that x= -3 and x = 6, which is correct. My question is whether or not -3 is a solution? when testing the

Question 973910: The integral of log3 (x^2) - log3 (x+6)= 1. After solving this I find that x= -3 and x = 6, which is correct. My question is whether or not -3 is a solution?
when testing the original question should it be:
A) log3 (-3^2) - log3 (-3 + 6) =1 in which case -3 is a solution, or should it be
B) 2log3 (-3) - log3 (-3 +6) =1, in which case -3 is not a solution because the first term, log3 (-3), does not exist? Thanks
Answer by addingup(3677) (Show Source): You can put this solution on YOUR website!
You have the correct solution.
(log(x^2))/(log(3))-(log(x+6))/(log(3)) = 1. Now I multiply both sides by log(3)
log(x^2)-log(x+6) = log(3)etcetera. You've already done the problem so it saves me some writing.
You factor the left and get:
(x-6) (x+3)= 0
x-6= 0 or x+3= 0
x= 6 or x= -3 This is your solution

RELATED QUESTIONS
solve:... (answered by nerdybill)

solve log3(x-3) + log3(x+2) = log3... (answered by rothauserc)

I have been told I need to turn my logs into exponents to solve this equation but I am... (answered by ewatrrr)

Solve the logarithmic equation for x. log3 4 + log3 x = log3 6 + log3(x −... (answered by stanbon,nakaguma)

log3(3x+6)-log3(x-6)=2 (answered by Marth,nerdybill)

log3(x-6)=3 (answered by stanbon)

Given that,P=log3(x-2)+ log3 (2x+1), determine the value of x for which P is... (answered by Fombitz)

simplify the expression log3 (x+1) -log3 (3x^2-3x-6)+log3 (x-2) The 3 on each log is... (answered by josgarithmetic)

Log3(x+1)-log3(x)+log3(3) (answered by Alan3354)