SOLUTION: solve for x: 2^(x-1) = 3^(2x+1) Answer is: Log2+log3/log2-2log3 = -1.191 Please help to arrive at answer. Thank you! Tiffany

Algebra.Com
Question 972068: solve for x: 2^(x-1) = 3^(2x+1) Answer is: Log2+log3/log2-2log3 = -1.191
Please help to arrive at answer.
Thank you!
Tiffany

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!



Apply logs to both sides (to isolate exponents)


Use rule 3 (from this link)


Distribute


Add to both sides.


Subtract from both sides.


Factor out the GCF x


Divide both sides by to isolate x.


Rearrange terms. This is the exact answer in terms of logs.


Use a calculator to get the approximate answer


Round to 3 decimal places (again this is approximate)

RELATED QUESTIONS

log8(3x-2)=2 log2(4x)-log2(3=6) 4e^2x+1=12 log6(x+6)+log6(2=2) log3[log2(x+5)]=1... (answered by stanbon)
Solve for x Log2(10x)=log2(3x+14) 2log3^x=log3^4 Log5(4x-3)=log5(x+1) (answered by Alan3354)
Please help me solve this task: Sqrt(log2((2x-3)/(x-1)))<1 log2 is logarithm base (answered by rothauserc)
Solve using logs 3^2n = 3 x 6^n+3. Please show your work. I somehow got n= (2log3 -... (answered by Alan3354)
Log2(2x+1) = log2 (x+2) - log2 3 Could you please break this problem down for me step by (answered by stanbon)
log2(x-1)+ log2 (x-4)=log2(2x-6)?what is the answer? (answered by jsmallt9)
How do you solve: log2(3x+2)-log2(x)/log2(4)=3 3log2(x-1)+log2(4)=5 Logx(1/27)=3... (answered by stanbon)
Please help me solve this problem log2(2x) - log2(x + 1) = -3 (answered by solver91311,math_helper)
solve for x:... (answered by MathLover1)