SOLUTION: log (x^2+x-6)^2 to base x+1 = 4
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Question 971464: log (x^2+x-6)^2 to base x+1 = 4
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log (x^2+x-6)^2 to base x+1 = 4
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-->
2x+1 = x-6
x = -7 --> base -6, not allowed
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(2x + 5)*(x - 1) = 0
x = 1 --> log(-4) not allowed
x = -5/2 --> base -1.5 not allowed
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