SOLUTION: x^2e^x+xe^x-e^x =0

Question 971069: x^2e^x+xe^x-e^x =0
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
x^2e^x+xe^x-e^x =0
------

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=5 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.618033988749895, -1.61803398874989. Here's your graph:

==========
x = as shown.

RELATED QUESTIONS
x^2e^x+xe^x-e^x... (answered by Alan3354)

x^2 e^x... (answered by solver91311)

please solve this equation x^2e^-2x -xe^-2x... (answered by Fombitz)

(e^2x)-(2e^x)-15=0 (answered by lwsshak3)

e^(2x)-2e^x+1 =0... (answered by lwsshak3)

solve: {{{e^(2x) - 2e^x... (answered by nerdybill)

∫e^√x / √x dx= (A) 2e^√x+C (B) 1/2e^√x+C (C)... (answered by Alan3354)

solve the equation: x^2 e^x + xe^x - e^x =... (answered by Alan3354)

solve for x e^2x - 2e^x - 8 =... (answered by lwsshak3)