SOLUTION: find x if x^log a base 2 + a^log x base 2 = 2a^2 (a>0)
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Question 970600: find x if x^log a base 2 + a^log x base 2 = 2a^2 (a>0)
Answer by anand429(138) (Show Source): You can put this solution on YOUR website!
Given,
.
.
=> x^(log(x,a)/log(x,2))+ (using
.
=> a^(1/(log(x,2)))+
=>
=>
Comparing exponents, we get,
=>
=>
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