SOLUTION: x^log a base 2 + a^log x base2 = 2a^2
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Question 970599: x^log a base 2 + a^log x base2 = 2a^2
Answer by anand429(138) (Show Source): You can put this solution on YOUR website!
Already solved,but here it is again if u missed it.
.
.
=> x^(log(x,a)/log(x,2))+ (using
.
=> a^(1/(log(x,2)))+
=>
=>
Comparing exponents, we get,
=>
=>
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