You must learn that any logarithm equation of the form: A = logBC is by definition always equivalent to the exponential equation: C = BA Therefore the equation log2x = 3 which is the same as 3 = log2x is equivalent to x = 23, which is x = 2, or x = 8 Edwin
Solve for x (log3x)2 + log3x2 + 1 =...(answered by Edwin McCravy)
can someone help me solve: given...(answered by Edwin McCravy)