SOLUTION: I previously asked a question. I just caught my mistake. The equation should have been this: log6(7x-2)=1+log6(x+5)

Question 965380: I previously asked a question. I just caught my mistake. The equation should have been this:

log6(7x-2)=1+log6(x+5)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
log6(7x-2)=1+log6(x+5)
:
subtract log6(x+5) from both sides
log6(7x-2) - log6(x+5) = 1
:
subtraction means divide in logs

:
the exponent equiv

or just

:
multiply both sides by (x+5)
7x - 2 = 6(x + 5)
7x - 2 = 6x + 30
7x - 6x = 30 + 2
x = 32
RELATED QUESTIONS
I need help with this question. solve the equation:... (answered by poliphob3.14)

Hey guys, I'm having a bit of trouble finding out a few things about the graph of y =... (answered by ccs2011)

How do I write the expression as a single logarithm with exponents.... (answered by Alan3354)

solve (3^2x) -[5(3^x)]=-6 I've tried a few different roots..nothing seems to be... (answered by Alan3354)

Please tell me if I am doing this right, the equation is {log6 (x+3) + log6 (x+4)= 1} I... (answered by richwmiller,Alan3354)

log6(2x-5)+1=log6(7x+10) (answered by jsmallt9)

The question states: Solve each logarithmic equation 1.) log(3x-1)=log(x-3)+log6... (answered by Theo)

May i please ask for some help to solve the following logarithm question by solving 'x'? (answered by erica65404)

Hi I couldnt figure out how to do this problem... (answered by stanbon)