SOLUTION: 3^5x=27^2x+1

SOLUTION: 3^5x=27^2x+1

Algebra.Com

Question 960182: 3^5x=27^2x+1
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use parentheses!!
3^(5x)=27^(2x+1)
.
.

RELATED QUESTIONS
Solve: (3/5)^-x = 125/27. Solve: 7^2x = 1/49 Solve: 5x+1 =... (answered by stanbon)

Solve the logarithm and check. 1). 3^5x=27^2x+1 2). 5^5x-6=50 Thanks show... (answered by solver91311)

27^(2x+1)=1/3 (answered by robertb)

Solve 3^2x+1 = 27 (answered by Alan3354)

3(2x-1) sqrt =27 (answered by mananth)

2x+1=5x-3 (answered by checkley77)

Solve... (answered by jim_thompson5910)

27^x+1=3^2x+1 (answered by Earlsdon)

Solve 3^x-1=7 Write 6log4x+log4y as a single logarithm Solve. 3^2x-1 x (answered by stanbon)