SOLUTION: Solve: log y-1 = -log(y-9)
Algebra.Com
Question 956227: Solve: log y-1 = -log(y-9)
Answer by LinnW(1048) (Show Source): You can put this solution on YOUR website!
log(y-1) = - log(y-9)
log(y-1) = -1* log(y-9)
Notice that
will not work since this would make the value of y-9 in log(y-9) negative.
RELATED QUESTIONS
solve:
log(Y-1)(Y+2)=log(subscript 7) 7
(answered by ikleyn)
Solve the simultaneous equations.
log base 9 (xy^2) = 1/2
(log base 3 x) (log base 3 y) (answered by josgarithmetic)
Solve
i) {{{log(base3)(2x + 1) = 2 + log (base3) (3x - 11)}}}
ii) {{{log(base4)y + log... (answered by lwsshak3)
Please help me solve this
{{{ log( 2, x ) + log( 4, y ) + log( 4, z ) }}}
{{{ log( 3, (answered by lwsshak3)
Rewrite each as an equivalent exponential equation.
1) log(3)5=y
2 log(a)7=-2... (answered by ankor@dixie-net.com)
log 9 y = − 1... (answered by josgarithmetic,MathLover1,greenestamps)
Please help me solve this simultaneous equation:
log x base 3 = y = log (2x-1) base 9
(answered by Edwin McCravy)
y=log(x-1) (answered by MathLover1)
y=log 1/2x
(answered by Alan3354)