SOLUTION: How do I graph y=2log(x-3)? I have the asymptope which is x=3

Algebra.Com
Question 950668: How do I graph y=2log(x-3)? I have the asymptope which is x=3
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!
I assume you have log base

first, the vertical asymptote of y =2log(x-3) is at
you also need to remember that logs are not defined for or for ,
so, the vertical asymptote is at , you just start with because will give you which is , and work from there, using the definition of the log, make a table
|....
|...........
|.......
|.........
|...........
plot these points and draw a line through


RELATED QUESTIONS

f(x)=8x^3/(x^2-1)(2x+1) what is the horizontal... (answered by Fombitz)
How do I graph y < x -... (answered by jim_thompson5910)
how do I graph x + y <=... (answered by solver91311)
how can i solve... (answered by solver91311)
How do I graph the x>3? (answered by josgarithmetic)
How do I graph the equation y=x+3? (answered by checkley75)
How do i graph the Asymptote ? y = 1/x =... (answered by Theo)
How do I graph y=(x+3)^2-9? Since I don't have a middle... (answered by wilft1)
Can you help me please? Graph x=3(y-1)+6 so far I have x=3(y-1)+6 X= 3y - 3 +... (answered by Alan3354)