SOLUTION: The amount C of cobalt-60 (in grams) in a storage facility at time t is given by C(t) = 25e^-.14t
where time is measured in years.
How long will it take for the original amo
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Question 948784: The amount C of cobalt-60 (in grams) in a storage facility at time t is given by C(t) = 25e^-.14t
where time is measured in years.
How long will it take for the original amount of 25 grams of the cobalt-60 to decay to half this amount. (This time is known as the half-life of cobalt-60.)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The amount C of cobalt-60 (in grams) in a storage facility at time t is given by C(t) = 25e^-.14t
where time is measured in years.
How long will it take for the original amount of 25 grams of the cobalt-60 to decay to half this amount. (This time is known as the half-life of cobalt-60.)
use the nat logs
log equiv of exponents
Find the ln of .5 (the ln of e is 1)
-.14t = -.693
t =
t = 4.95 yrs
:
:
Check this on your calc: enter 25*e^(-.14*4.95)
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