SOLUTION: Solve fora in log(2a)- 3log2= 1/2log(a-3)

Question 946643: Solve fora in log(2a)- 3log2= 1/2log(a-3)
Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!

Solve for in

...if log same, then
...square both sides

...factor completely
...group

solutions:
if =>
if =>

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve for a in log(2a)- 3log2= 1/2log(a-3)
log(2a)- 3log2= 1/2log(a-3)
log(2a/(2^3))=log((a-3)^(1/2))
2a(2^3)=(a-3)^(1/2)
16a=√(a-3)
square both sides:
256a^2=a-3
256a^2-a+3=0
b^2-4ac<0
no real solution

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