SOLUTION: Log2^x+log4^x+log8^x=21/4, find x
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Question 945773: Log2^x+log4^x+log8^x=21/4, find x
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Log2^x+log4^x+log8^x=21/4, find x
6x=21/4log2
x=21/(24log2)
x≈2.9067
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