SOLUTION: How do I solve the equation {{{ log2x=4-3logx2 }}} ?

Algebra.Com
Question 939657: How do I solve the equation ?
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
Convert to a log


( Is this the equation? Hope so )








Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
log2x=4-3logx2
------------
log(2x) = 4 - log(x^2)^3
----
log(2x) + log(x^6) = 4
----
log[2x*x^6] = 4
----
log[2x^7] = 4
---
2x^7 = 10^4
-----
x^7 = 10000/2 = 5000
-----
x = 5000^(1/7)
------
x = 3.376..
Cheers,
Stan H.
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