SOLUTION: hello Teachers:can you help with this log problem? 3log2x=4...that x is a exp above the log2.-this is what I did. I moved the 3above the x and the put it in exp.form.And I did this

Question 935531: hello Teachers:can you help with this log problem? 3log2x=4...that x is a exp above the log2.-this is what I did. I moved the 3above the x and the put it in exp.form.And I did this to change it to exp. form...2exp.4=x exp.3..is this right?tks for any help
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Your described given equation: , and you did not indicate the base.

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