SOLUTION: Can you please help me solve this? I think I got the answer, but I am not sure. e^(x^2)=e^(x) * e^(6) I multiplied (e^x and e^6, which meant adding the exponents) e^(x^2)

Question 923463: Can you please help me solve this? I think I got the answer, but I am not sure.
e^(x^2)=e^(x) * e^(6)
I multiplied (e^x and e^6, which meant adding the exponents)
e^(x^2)= e^(x+6)
Then got rid of the base e on both sides
x^2=x+6
(-x^2)+x+6=0
x=-2 x=3
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Yes. Good Work.
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
The solution process and answer result are good.

A couple of formal differences could be made in place.

You would "take the log_base_e of both sides" at

The next step will give a more convenient form to work with,

Easy enough to factor,

Which give the solutions you found.
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