SOLUTION: solve for x: log(x + 9) = 1 - log(x - 8)
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Question 919449: solve for x: log(x + 9) = 1 - log(x - 8)
Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
solve for :
....since you have log base , we know that
so, we can write
...now we have log=log, then we can say that
........now solve for
........use quadratic formula to solve for
...you can leave like this or
solutions:
........ solution
......rounded
or
...we don't need negative solution for log
check: use solution
-true
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve for x: log(x + 9) = 1 - log(x - 8)
log(x+9)=1-log(x-8)
log(x+9)+log(x-8)=1
log((x+9)(x-8))=1
(x+9)(x-8)=10 (base(10) raised to log of number(1)=number(x+9)(x-8))
x^2+x-72=10
x^2+x-82=0
solve for x by quadratic formula:
a=1, b=1, c=-82
x=(√(329)-1)/2≈8.56 (Ignore negative root)
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