SOLUTION: Can you show me how to solve e^(5ln3 - 4ln5) using the properties of logarithms? The answer is 243/625, but I want to know step by step how to get there? Thank you!
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Question 917571: Can you show me how to solve e^(5ln3 - 4ln5) using the properties of logarithms? The answer is 243/625, but I want to know step by step how to get there? Thank you!
Found 2 solutions by Hawksfan, MathTherapy:
Answer by Hawksfan(61) (Show Source): You can put this solution on YOUR website!
e^(5ln3 - 4ln5)
Properties:
1) e^(lnx) = x
2) ln(x-y) = ln[x/y]
3) alnb = lnb^a
by #3 e^(ln3^5 - ln5^4)
simplify e^(ln 143 -ln625)
by rule #2 above e^(ln143/625)
by rule #1 above 143/625 because the e cancels the ln
answer is 143/625
e
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Can you show me how to solve e^(5ln3 - 4ln5) using the properties of logarithms? The answer is 243/625, but I want to know step by step how to get there? Thank you!
Let
Then
Therefore,
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