SOLUTION: Evaluate the log expression: {{{8^((log((base8))20))}}} So I know that log(base a)(b^r) = r log (base) b But I get lost on how to continue to break it down further from that it

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Question 914189: Evaluate the log expression:
So I know that log(base a)(b^r) = r log (base) b
But I get lost on how to continue to break it down further from that it wouldn't be log(base 8) (20^8)?
Please help me figure this out
Found 3 solutions by josgarithmetic, MathLover1, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
INVERSE FUNCTIONS...
Do you recognize their use or occurrence in the expression?
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!



=8^(log(20)/log(8))


=8^(log(2^2*5)/log(2^3))

=8^((2log(2)+log(5))/(3log(2))) ......plug in values




=8^((2(0.30102)+(0.69897))/(3(0.30102)))

=8^((0.60204+0.69897)/0.90306))

=8^(1.30101/0.90306)

=

= round

=


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!
Evaluate the log expression:
So I know that log(base a)(b^r) = r log (base) b
But I get lost on how to continue to break it down further from that it wouldn't be log(base 8) (20^8)?
Please help me figure this out


Let  = x

 -------Converting to LOGARITHMIC FORM

Thus,  

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