SOLUTION: Given that log(basea)2=.693, log(basea)6=1.792, and log(basea)4=1.386, find log(basea)48
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Question 913465: Given that log(basea)2=.693, log(basea)6=1.792, and log(basea)4=1.386, find log(basea)48
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The log of the product is the sum of the logs, so:
\ =\ \log_a\left(2\cdot 4\cdot 6\right)\ =\ \log_a(2)\ +\ \log_a(4)\ +\ \log_a(6))
You can do your own arithmetic.
John
My calculator said it, I believe it, that settles it
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