SOLUTION: log(6x-3)base 3=1+log(x-3)base3)
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Question 905391: log(6x-3)base 3=1+log(x-3)base3)
Answer by harpazo(655) (Show Source): You can put this solution on YOUR website!
Since the bases of the logs are the same (number 3 in this case), then the insides must be equal. That is:
6x - 3 = 1 + x - 3
6x - x = 3 - 3 + 1
5x = 1
x = 1/5
Understand?
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