SOLUTION: I have a logarithmic expression to condense
Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1)
I know it can be written as
log (x+1)^3 + log (9x+1)^5 - log (x+1)
but i'm lost
Question 901583: I have a logarithmic expression to condense
Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1)
I know it can be written as
log (x+1)^3 + log (9x+1)^5 - log (x+1)
but i'm lost after this how can i condense this further. help Found 2 solutions by solver91311, stanbon:Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the logs is the log of the product. The difference of the logs is the log of the quotient.
So
John
My calculator said it, I believe it, that settles it
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! I have a logarithmic expression to condense
Equation: 3 log (x+1) + 5 log(9x+1)- log(x+1)
I know it can be written as
log (x+1)^3 + log (9x+1)^5 - log (x+1)
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log[(x+1)^3*(9x+1)^5/(x+1)]
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= log[(x+1)^2*(9x+1)^5]
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Cheers,
Stan H.
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