SOLUTION: I have tried so many times to solve this equation but Im stuck:
4*3^x=6*5^x
the furthest I gotten is: (4)x log(3)= (6) x log (5) but I don't know where to go from here
Algebra.Com
Question 898460: I have tried so many times to solve this equation but Im stuck:
4*3^x=6*5^x
the furthest I gotten is: (4)x log(3)= (6) x log (5) but I don't know where to go from here
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
4*3^x=6*5^x
-----------
Don't use x for multiply, it's already in use.
Use * (Shift 8)
---
4*3^x=6*5^x
log(4) + x*log(3) = log(6) + x*log(5)
x*(log(3) - log(5)) = log(6) - log(4)
x*log(3/5) = log(3/2)
x = log(1.5)/log(0.6)
RELATED QUESTIONS
I am trying to solve a logarithmic equation and have gotten an answer but its not the... (answered by Alan3354)
log base 3 (x) = log base 3 (1/x)+4
i understand that log base 3 (1/x) is subtracted... (answered by solver91311)
please help solve this equation: {{{2log x-6 = 4}}}
i have tried using the log power... (answered by scott8148)
I need help on this problem.
3^(x+4) = 6^(2x+5)
solve for x by taking the log of both (answered by lwsshak3)
the question is to solve for x ..
log base 3 (2x+5) - Log base 3 (x-8) =1
ive gotten (answered by Alan3354,timvanswearingen)
I tried this problem, but the answer that I got doesn't seem right to me. Any help would... (answered by Earlsdon)
log((x+3)(x-8))+ log((x+3)\(x-8)) = 2
I tried but i cannot solve this equation, whose... (answered by lwsshak3)
This question has been bothering me for quite a while now.
4 x 5^(X+2) = 5 x 4^(2X)
(answered by stanbon)
5^x=4^(x+1)
I can't figure out how to solve this the answer is 6.2126 but I get as far (answered by ccs2011)