SOLUTION: log base 2 (log base 3 (log base 5 of x)) = 0

Question 895678: log base 2 (log base 3 (log base 5 of x)) = 0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log base 2 (log base 3 (log base 5 of x)) = 0
-----
log2[log3(log(x)/log(5)) = 0
-----
log2[log[log(x)/log(5)]/log(3)] = 0
-----
log[log[log[log(x)/(log(5)*log(3))]/(log(2)) = 0
-----
log[log[log(x)/(log(5)*log(3)*log(2))] = 0
-----
log[log(x)/(log(5)*log(3)*log(2))] = 1
log(x)/(log(5)(log(3)*log(2))/ = 10
log(x) = 10*log(5)*log(3)(log(2))
log(x) = 1.0039
x = 10*1.0039
x = 10.0906
==============
Cheers,
Stan H.
-------------------

RELATED QUESTIONS
how do you solve log base 4 (log base 3 (log base 2 of X)) = 0?? (answered by stanbon)

0= log base 5 (x-2) - log base 5... (answered by MathLover1)

log (base 3) x + log (base 5) 4x =... (answered by josgarithmetic)

log base 2 (x-2)+log base 2(8-x)-log base... (answered by stanbon)

find x if log 6 base 3 + log x base 3 - log 5 base... (answered by lwsshak3)

log base 3 of X = 1/2 log base 3 of 25 - 5 log base 3 of... (answered by josgarithmetic)

log(base... (answered by Fombitz)

Solve for x: (A.) (5/2) log(base 4)4 = log(base 4)(2x-3) (B.) Log(base 3)(x+2)-... (answered by stanbon)

if log [base x] (3) - log [base 2] (a) = log [base 3] (a), express log [base x] in terms... (answered by jsmallt9)