SOLUTION: How to solve
22) 2^x-1 = 8^-2x
33) write a formula
y= -3+f(x-2)
48) write in logarithmic form
127= 2 (10^0.5x)- 17.3
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Question 88534This question is from textbook modeling, functiongs, and graphs
: How to solve
22) 2^x-1 = 8^-2x
33) write a formula
y= -3+f(x-2)
48) write in logarithmic form
127= 2 (10^0.5x)- 17.3
This question is from textbook modeling, functiongs, and graphs
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve
22) 2^x-1 = 8^-2x
2^(x-1) = 2^[3(-2x)
2^(x-1) = 2^-6x
The exponents must be equal:
x-1 = -6x
7x = 1
x = 1/7
---------------------------
33) write a formula
y= -3+f(x-2)
Comment: that doesn't make any sense.
------------------
48) write in logarithmic form
127= 2 (10^0.5x)- 17.3
144.3 = 2(10^0.5x)
72.15 = 10^0.5x
Take the log of both sides to get:
0.5x = log72.15
0.5x = 1.858236...
x = 3.71647...
===============
Cheers,
Stan H.
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